GATE Chemistry 2011
Previous Year Question Paper with Solution.
1. Jahn-Teller distortion of CuSO4.5H2O acts to
(a) raise symmetry
(b) remove an electronic degeneracy
(c) cause loss of H2O ligand
(d) promote a d-electron to an antibonding molecular orbital
Ans. (b)
Sol. In CuSO4 · 5H2O, Cu is present as Cu2+.
Cu2+ = [Ar] 3d9
It is clear that the two out of three electrons in eg orbitals can occupy either orbital or orbital.
Since, the eg level is not symmetrically filled, Jahn-Teller distortion occurs. This removes the degeneracy of the eg and t2g levels. Thus, the complex is distorted.
Correct option is (b)
2. Among the following, the group of molecules that undergoes rapid hydrolysis is:
(a) SF6, Al2Cl6, SiMe4
(b) BCl3, SF6, SiCl4
(c) BCl3, SiCl4, PCl5
(d) [Xe2F3]+[AsF6]–
Ans. (c)
Sol. Out of these compounds BCl3, SiCl4 have vacant orbitals, hence H2O can attack to them easily and they show rapid hydrolysis.
SF6 is spherical with stronger S–F bonds as well as steric hinderance hence it is not hydrolysed. PCl5 also vacant orbitals and hence can show hydrolysis.
PCl5 + H2O POCl3 + 2HCl (partial hydrolysis)
PCl5 + 4H2O H3PO4 + 5HCl (complete hydrolysis)
SiMe4 has steric repulsion hence H2O can't attack, showing no hydrolysis. Hence BCl3, SiCl4, PCl5 show more rate of hydrolysis.
Correct option is (c)
3. The reaction of solid XeF2 with AsF5 in 1:1 ratio affords
(a) XeF4 and AsF3
(b) XeF6 and AsF3
(c) [XeF]+[AsF6]–
(d) [Xe2F3]+[AsF6]–
Ans. (c)
Sol. XeF2 + AsF5 [XeF]+ [AsF6]–
Correct option is (c)
4. A well known naturally occuring organometallic compound is:
(a) vitamin B12 coenzyme
(b) chlorophyll
(c) cytochrome p-450
(d) myoglobin
Ans. (a)
Sol. Vitamin B12 co-enzyme is naturally occuring organometallic compound.
Correct option is (a)
5. The complex that exists as a pair of enantiomers is
(a) trans-[Co(H2NCH2CH2NH2)2Cl2]+
(b) cis-[Co(NH3)4Cl2]+
(c) [Pt(PPh3)(Cl)(Br)(CH3)]–
(d) [Co(H2NCH2CH2NH2)3]3+
Ans. (d)
Sol. Complexes of the type [M(aa)3], [M(aa)2b2], M[(aa) b2c2] exhibit optical isomerism and exist as a pair of enantiomers.
Thus, [Co(H2NCH2CH2NH2)3]3+ exists as a pair of enantiomers. The structure of its enantiomers are as
Correct option is (d)
6. The region of electromagnetic spectrum employed in the electron spin resonance (ESR) spectroscopy is:
(a) radiowave
(b) microwave
(c) infrared
(d) visible
Ans. (b)
Sol. The region of electromagnetic spectrum employed in the electron spin resonance (ESR) is microwave [3 × 1010 – 3 × 1012 Hz]
Correct option is (b)
7. The red color of oxyhemoglobin is mainly due to the
(a) d-d transition
(b) metal to ligand charge transfer transition
(c) ligand to metal charge transfer transition
(d) intraligand transition.
Ans. (d)
Sol. Red colour of oxyhemoglobin is mainly due to transition in porphyrin system
Correct option is (d)
8. The band structure in an n-type semiconductor is
(a) I
(b) II
(c) III
(d) IV
Ans. (a)
Sol. In semiconductors there appears an impurity band between valence band and conductivity band.
In n-type of semiconductor the impurity band contain electrons while in p-type conductors impurity band is empty.
But in both case the impurity band show bridge between valence band and conduction band.
Correct option is (a)
9. In the following reaction
The major product [X] is:
(a)
(b)
(c)
(d)
Ans. (b)
Sol.
Correct option is (b)
10. In the following reaction sequence
the major product [X] is:
(a)
(b)
(c)
(d)
Ans. (a)
Sol.
Correct option is (a)
11. The diene which undergoes Diels-Alder reaction with maleic anhydride is:
(a)
(b)
(c)
(d)
Ans. (a)
Sol.
Correct option is (a)
12. The sequence of an mRNA molecule produced from a DNA template strand with the composition 5'–AGCTACACT–3' is
(a) 5'–AGUGUAGCU–3'
(b) 5'–UCGAUGUGA–3'
(c) 5'–AGTGTAGCT–3'
(d) 5'–TCGATGTGA–3'
Ans. (c)
Sol.
Correct option is (c)
13. In the following reaction,
the major product [X] is:
(a)
(b)
(c)
(d)
Ans. (b)
Sol.
Correct option is (b)
14. The structure of the dipeptide Ala-Pro derived from the natural amino acids is:
(a)
(b)
(c)
(d)
Ans. (a)
Sol. Ala-Pro
In this dipeptide alanine is at N–T-A.A. So, NH2 group of Ala should be free and proline is at C-T-AA. So, group should be free at Pro and both amino acid have 'S' configuration. So, it should be maintained ion the product also.
Correct option is (a)
15. In the following reaction
the major product [X] is:
(a)
(b)
(c)
(d)
Ans. (c)
Sol.
Correct option is (c)
16. In the following reaction,
the major product [X] is:
(a)
(b)
(c)
(d)
Ans. (a)
Sol.
Correct option is (a)
17. For a given first order reaction, the reactant reduces to 1/4th its initial value in 10 minutes. The rate constant of the reaction is:
(a) 0.1386 min–1
(b) 0.0693 min–1
(c) 0.1386 mol L–1 min–1
(d) 0.0693 mol L–1 min–1
Ans. (a)
Sol.
Correct option is (a)
18. The freezing point constant for water is 1.86 K (mol kg–1)–1. The change in freezing point when 0.01 mol glucose is added to 1 kg water is:
(a) 1.86 K
(b) –1.86 K
(c) 0.186 K
(d) –0.0186 K
Ans. (d)
Sol. Depression in freezing point
= i.kf.x
Glucose is non electrolyte i = 1
kf = 1.86k (mol/kg)–1
Molality (m) = = 0.01
= 1 × 1.86 × 0.01 = 0.0186
Tf = 0 – 0.0186 = – 0.0186
Correct option is (d)
19. On the pressure-temperature diagram for a one-component system, the point where the solid-liquid and the liquid-gas curves intersect is:
(a) triple point
(b) critical point
(c) melting point
(d) boiling point
Ans. (a)
Sol. Triple point is the piont on the P – T diagram for one compnent systement at which the solid-liquid and the liquid gas curves intersect. At this point all three phases (solid and vapour) can co-exist in equilibrium.
Correct option is (a)
20. The wave function for a harmonic oscillator described by Nx has
(a) One maximum only
(b) One maximum, one minimum only
(c) Two maxima, one minimum only
(d) Two maxima, two minima only
Ans. (b)
Sol.
Further differentiation,
Hence, one maxima and one minima.
Correct option is (b)
21. If an arbitrary wave function is used to calculate the energy of a quantum mechanical system, the value calculated is never less than the true energy.
The above statement relates to
(a) Perturbation theory
(b) Variation principle
(c) Heisenberg's uncertainty principle
(d) quantization of energy
Ans. (b)
Sol. From variation principle, if we are used an arbitary wave function and calculate the energy of a quantum mechanical system the value calculated is never less than the true energy. This principle used for the validity of function.
> E0
Where, = energy calculated
E0 = energy system.
Correct option is (b)
22. The point group symmetry of the given planar shape is:
(a) D3h
(b) C3
(c) C3h
(d) C3v
Ans. (c)
Sol.
1C3 axis, Hence, C3h point group
Correct option is (c)
23.
(a) V
(b) S
(c) –S
(d) –V
Ans. (a)
Sol. dG = VdP – SdT (from Maxwell)
At constant temperature dT = 0
Correct option is (a)
24.
According to Ehrenfest classification of phase transitions, the above diagram refers to
(a) Zeroth order phase transition
(b) First order phase transition
(c) Second order phase transition
(d) transition
Ans. (b)
Sol. Main characteristics of first-order transitions are:
(1) The chemical potential is a continuous function of temperature.
(2) The derivatives of chemical potential are discontinuous.
Correct option is (b)
25. According to conventional transition state theory, for elementary bimolecular reactions, the molar entropy of activation is:
(a) Positive
(b) Zero
(c) Negative
(d) Positive for endothermic and negative for exothermic reactions.
Ans. (c)
Sol. According to conventional transition state theory for elementary bimolecular reactions the molar entropy of activation . is negative because two reactant species come together to form one species.
for Bimolecular Reactions is – 1
Correct option is (c)
26. The crystal field stabilization energy (CFSE) value, for [Ti(H2O)6]3+ that has an absorption maximum at 492 nm is
(a) 20,325 cm–1
(b) 12,195 cm–1
(c) 10,162 cm–1
(d) 8,130 cm–1
Ans. (d)
Sol. Absorption maximum, = 492 nm
= 492 × 10–7 cm
= 20325 cm–1
CFSE = – 0.4
= – 0.4 × 20325
= 8130 cm–1
Correct option is (d)
27. For Et2AlX (X = , Ph–, Cl–1 and H–), the tendency towards dimeric structure follows the order
(a)
(b)
(c)
(d)
Ans. (d)
Sol. Correct option is (d)
28. In the isoelectronic series, VO43–, CrO42– and MnO4– all members have intense charge transfer (CT) transitions. The incorrect statement is
(a) CT transitions are attributed to excitations of electrons from ligand (σ) to metal (e)
(b) MnO4– exhibits charge transfer at shortest wavelength among the three
(c) The wavelengths of transitions increase in the order VO4–3 < CrO4–2 < MnO4–
(d) The charge on metal nucleus increases in the order VO4–3 < CrO4–2 < MnO4–
Ans. (b)
Sol. CT (charge transfer) transitions are attributed to excitations of electron from ligand to metal or vice-versa.
Higher the oxidation state of metal, higher is the wavelength of transition.
Order of oxidation state is
V5+ < Cr6+ < Mn7+
The order of wavelength of transition is
MnO4– have high oxidation state.
So, energy gap will be less and wavelength will be maximum.
Correct option is (b)
29. The increasing order of wavelength of absorption for the complex ions
(i) [Cr(NH3)6]3+
(ii) [CrCl6]3–
(iii) [Cr(OH2)6]3+
(iv) [Cr(CN)6]3– is
(a) iv < ii < i < iii
(b) iv < iii < ii < i
(c) iv < i < iii < ii
(d) ii < iii < i < iv
Ans. (c)
Sol. Ligand strengh Cl– < H2O < NH3 < CN–
Cr3+ CFSE = Cl– < H2O < NH3 < CN–
So, Cl– > H2O > NH3 > CN–
So, correct option is (c)
30. The total number of metal-metal bonds in Ru3(CO)12 and Co4(CO)12, respectively, is
(a) 3 and 6
(b) 4 and 5
(c) zero and 4
(d) 3 and 4
Ans. (a)
Sol. Ru3(CO)12 TVE 3 Ru 8 × 3 = 24 electron
12CO 12 × 2 = 24 electron
TVE = 48 electron
B = n × 18 – TVE, n = number of metal
= 3 × 18 – 48
= 54 – 48 = 6
= number of M—M bond ; = 3 (M—M bond)
Co4(CO)12 = TVE
4Co 4 × 4 = 36 electron
12CO 12 × 2 =
B = n × 18 – TVE = 4 × 18 – 60 = 12 ; = 6 (M—M bond)
Correct option is (a)
31. According to VSEPR theory the shapes of [SF2Cl]+ and [S2O4]2– should be
(a) trigonal planar for [S2O4]2– and trigonal pyramidal for [SF2Cl]+
(b) both trigonal planar
(c) trigonal pyramidal for [S2O4]2– and trigonal planar for [SF2Cl]+
(d) both trigonal pyramidal
Ans. (d)
Sol. The Hybridised sp3 in [SF2Cl]+.
hence, the shape will by trigonal pyramidal.
In [S2O4]2– (Dithionite ion) 's' is sp3 hybridised by the S–S bond length are longer than that in polysulphites hence lp–lp repulsion is minimum.
Due to this here SO2 planes almost parallel (dihedral angle is 30°) giving if (especially (SO2–) unit) a planar eclipsed structure.
Correct option is (d)
32. The product of the reaction between CH3Mn(CO)5 and 13CO is:
(a) (CH313CO)Mn(CO)5
(b) (CH3CO)Mn(CO)4(13CO)
(c) (13CH3CO)Mn(CO)5
(d) CH3Mn(CO)4
Ans. (b)
Sol.
Correct option is (b)
33. The correct pair of 1H and 31P NMR spectral patterns for C(H)(F)(PCl2)2 is:
(a)
(b)
(c)
(d)
Ans. (c)
Sol. The correct pair 1H and 31P NMR
C(H) (F) (PCl2)2
1H NMR (2NI + 1) (2NIP + 1)
31P NMR (2NIF + 1) (2NIH + 1)
Correct option is (c)
34. In the following reaction
the major product [X] is:
(a)
(b)
(c)
(d)
Ans. (d)
Sol.
Correct option is (d)
35. In the following reaction,
the major product [X] is:
(a)
(b)
(c)
(d)
Ans. (c)
Sol.
Correct option is (c)
36. In the following reaction,
the major product [X] is:
(a)
(b)
(c)
(d)
Ans. (a)
Sol.
Correct option is (a)
37. The most appropriate sequence of reactions for carrying out the following conversion
is
(a) (i) Peracid; (ii) H+; (iii) Zn/dil. HCl
(b) (i) Alkaline KMnO4; (ii) NaIO4; (iii) N2H4/KOH
(c) (i) Alkaline KMnO4; (ii) H+; (iii) Zn/dil. HCl
(d) (i) O3/Me2S; (ii) NaOEt; (iii) N2H4/KOH
Ans. (d)
Sol.
Correct option is (d)
38. In the following reaction sequence
the major product [X] is:
(a)
(b)
(c)
(d)
Ans. (d)
Sol.
Correct option is (d)
39. In the following conversion
the major product [X] is:
(a)
(b)
(c)
(d)
Ans. (a)
Sol.
Correct option is (a)
40. In the following reaction,
the major product [X] is:
(a)
(b)
(c)
(d)
Ans. (b)
Sol.
Correct option is (b)
41. In the reaction,
Optically pure (+)-trans-2-acetoxycyclohexyl tosylate
the major product [X] is:
(a) racemic trans-1, 2-cyclohexanediol diacetate
(b) optically active trans-1, 2-cyclohexanediol diacetate
(c) racemic cis-1, 2-cyclohexanediol diacetate
(d) optically active cis-1, 2-cyclohexanediol diacetate.
Ans. (a)
Sol.
Correct option is (a)
42. The activity of water at 11 bar and 298K is:
(a) 1.101
(b) 1.007
(c) 0.998
(d) 0.898
Ans. (a)
Sol. At NTP concentration of water = 55.5 mol/L
Correct option is (a)
43. For the process
assuming ideal gas behavior, the change in molar entropy is:
(a) –27.57 J K–1 mol–1
(b) +27.57 JK–1 mol–1
(c) –24.20JK–1 mol–1
(d) +24.20 JK–1 mol–1
Ans. (a)
Sol.
Correct option is (a)
44. The wave function for a quantum mechanical particle in a 1-dimensional box of length 'a' is given by
The value of 'A' for a box of length 200 nm is
(a) 4 × 104 (nm)2
(b)
(c)
(d) 0.1 (nm)–1/2
Ans. (d)
Sol. For one elimensional box
A = for one dimensional box normalisation constant
a = 200 nm
A =
Correct option is (d)
45. For 1 mole of a monoatomic ideal gas, the relation between pressure (p), volume (V) and average molecular kinetic energy is
(a)
(b)
(c)
(d)
Ans. (c)
Sol. PV = 1/3 MNu–2
PV = 2/3 N ×
Correct option is (c)
46. For a 1 molal aqueous NaCl solution, the mean ionic activity coefficient and the Deby-Huckel Limiting Law constant (A) are related as
(a)
(b)
(c)
(d)
Ans. (a)
Sol.
Correct option is (a)
47. For the concentration cell
M | M+ (aq, 0.01 mol dm–3) || M+ (aq, 0.1 mol dm–3) | M
the EMF (E) of the cell at a temperature (T) equals
(a)
(b)
(c)
(d)
Ans. (a)
Sol.
Correct option is (a)
Commond Data Questions:
Commond data for Q.48 and Q.49:
A hypothetical molecule XY has the following properties
Reduced mass: 2 × 10–26 kg
X–Y bond length: 100 pm
Force constant of the bond: 8 × 102 N.m–1
48. The frequency of radiation (in cm–1 units) required to vibrationally excite the molecule from v = 0 to v = 1 state is
(a) 3184.8
(b) 2123.2
(c) 106.1
(d) 840.0
Ans. (c)
Sol.
Wave number
Correct option is (c)
49. The frequency of radiation (in cm–1 units) required to rotationally excite the molecule from J = 0 to J = 1 state is
(a) 1.4
(b) 2.8
(c) 3.2
(d) 3.6
Ans. (b)
Sol. J = 0 to J = 1
Correct option is (b)
Common data for Q.50 and Q.51:
Na2HPO4 and NaH2PO4 on heating at high temperature produce a chain sodium pentaphosphate quantitatively.
50. The ideal molar ratio of Na2HPO4 to NaH2PO4 is:
(a) 4 : 1
(b) 1 : 4
(c) 3 : 2
(d) 2 : 3
Ans. (d)
Sol.
Correct option is (d)
51. The total charge on pentaphosphate anion is:
(a) –5
(b) –3
(c) –7
(d) –9
Ans. (c)
Sol. Na7P5O16 7Na+ + P5O167–
Correct option is (c)
Linked Answer Q.52 and Q.53:
The decomposition of ozone to oxygen 2O3(g) 3O2(g) occurs by mechanism
where, M is the catalyst molecule.
ki' are rate constants and Ka,i's the activation energies for the elementary steps,
52. Under the steady state approximation for the intermediates, the rate of decomposition of ozone, , is
(a)
(b)
(c)
(d)
Ans. (a)
Sol. r = K3 [O][O3]
Applying SSA on [O]
Rate of formation = Rate of consumption
K1[M][O3] = K2[O2][O][M] + K3[O][O3]; [O] =
r = K3[O3]
Rate of decomposition of ozone, = 2r
Correct option is (a)
53. Assuming k3[O3] >> k2[O2][M], the activation of the overall reaction is
(a)
(b) Ea,3 + Ea,1 – Ea,2
(c) Ea,2
(d) Ea,1
Ans. (d)
Sol.
Correct option is (d)
Statement for Linked Answer Q.54 and Q.55:
A ketone on treatment with bromine in methanol gives the corresponding monobromo compound[X] having molecular formula C5H9BrO. The compound [X] when treated with NaOMe in MeOH produces [Y] as the major product. The spectral data for compound [X] are: 1H NMR: 1.17(d, 6H), 3.02 (m, 1H), 4.10(s, 2H); 13C NMR: 17, 37, 39, 210.
54. The compound [X] is:
(a)
(b)
(c)
(d)
Ans. (d)
Sol.
Correct option is (d)
55. The major product [Y] is:
(a)
(b)
(c)
(d)
Ans. (b)
Sol.
Correct option is (b)